Consider the reaction 4PH3(g) ---> P4(g) + 6H2(g) If in a certain experiment, over a specific...
Consider the reaction
4PH3(g) ---> P4(g) + 6H2(g)
If in a certain experiment, over a specific time period, 0.0048 mole of PH3 is consumed in a 2.0 L container per second of a reaction. What is the rate of reaction?
Homework Answers
![Gin еалиб: 4. Pz.g) P4 9) + 6H2 9) mules of PH₂ consumed = 0.0048mul Volume = 2.0L D[PH₂] = consumphon = 0.0048 mol 2002 0.00](http://img.homeworklib.com/questions/40278a10-c6c7-11ea-a7c1-7fdee8f41814.png?x-oss-process=image/resize,w_560)
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Consider the reaction
4PH3(g) ---> P4(g) + 6H2(g)
If in a certain experiment, over a specific...
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