Question

A spherical, concave, shaving mirror has a radius of curvature of 31.9cm .

Part A

What is the magnification of a person's face when it is 12.0cm to the left of the vertex of the mirror?

m=?

Part B

Where is the image?

s'=?

Answer 1

$\frac{1}{v} + \frac{1}{u} = \frac{2}{R}$

v= image distance

u = object distance = -12 cm

R = -31.9 cm (since, it is a concave mirror)

Calculating using the above equation, v = 48.455 cm on the right side of the mirror

$m = -\frac{v}{u}$

$m = -\frac{48.455}{-12}$

m=4.038