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Amperes Law was used to show that the magnitude of the magnetic field a distance R from a long, thin wire carrying current I is given by: 14. If a proton moving to the left at 1x105 m/s were to pass through Point C, what would be the magnetic force on that proton (both magnitude and direction must be correct for credit)? Ans: D a. 2.14z10N b. O N c. 11.2z10Nd. 7.46x10N 15.0A 250A 2TR 15. What is the direction of that force on the proton? Ans: B A right hand rule can be used to determine the direction of this magnetic field. b. Down c. Into dLeft 16. If the currents remain the same as found in above Two parallel wires, separated by a distance of 20 cm, are carrying currents. One wire carries a current of 15 A in the direction shown and the other carries a 25A current as shown. Point C is a distance of 10 cm to the right of the 15 A current and Point A is halfway between the two wires. (Show your work below and on the following page. Be sure to label to which section the work belongs) what will be the magnitude of the magnetic field for Point A (remember, this will be the result of both wires (dont forget to take account the directions of each B-field from each wire)? Ans: B A. 1.66x10 T C. 3.00x10 T 17. What will be the direction of the B-field at Point A? Ans: A b. Chat of the Color the left hand wire red and color the right hand wire green. Then, on the diagram, using correspondingly colored and to represent into and out of the page, respectively, show the magnetic field directions for each wire in all the regions left right, and in-between the wires 18. If a third current carrying wire is laid parallel to the original wires carrying a 5A current downward and passing through Point A, what will be the force per unit length on that wire (remember, there is a formula for the force on a current-carrying wire immersed in a magnetic field)? Ans: A 10. What is the magnitude of the B-field at Point C due to the 15 A current? Ans: C A. 1.66x10 T B. 2.00x10 T C. 3.00x10 D. 4.00x10 T A. 1.00x10N B. 2.00x10N C. 3.00x10N D. 4.00x10 N 11. What is the magnitude of the B-Field at Point C due to the 25 A current? Ans: A A. 1.66x10 T C. 3.00x10 T D. 4.00x10 T 12. What is the total magnetic field at Point C (both magnitude and direction must be correct for credit):? Ans: C a. 1.34z10 T b. 7.00x10 T c. 4.66x10 T d. 0 T 13. What is the DIRECTION of the total magnetic field at Point C? Ans: A a. Into o.Left d Out of

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o 30 5 13 Do 5T = 7472X1019 N, -5 -u

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