10. How much current (in A to one decimal place) is needed to produce 100 g...

Question

Question

Answer 1

Answer #1

Ans :

100 g of gold = 100 / 196.97 = 0.51 mol

Number of moles of electrons required = 0.51 x 3 = 1.53 mol

Charge in coloumbs = 1.53 x 96487 = 147625 C

Q = I.t

where Q is charge in coloumbs , I is current in A and t is time in seconds

147625 = I x 3.0 x 60 x 60

I = 13.6 A

Answer 2

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