1. Mean : x̄. The Volume mean is:
( 150 + 151 + 151 + 150 + 152 ) /5 = 150.8 uL
2. 100X to 1X by dilution using d-H2O :
Total volume : 5 L
volume stock needed : 1X / 100X * 5L = 0.05 L or 50 mL
Volume of d-H2O : 4.95 L
3. 10 g of solute dissolved in 0.8 L or 800 mL of water :
we take Volume of solution ~ 800 mL
% w/v = ( g/ mL * 100) = 10 g / 800 mL * 100 = 1.25 %
4.
3.5 w/v % solution :
% w/v = ( g/ mL * 100)
500 mL solution contains : 0.035 * 500 = 17.5 g
since, 1g = 1000 mg
thus, amount of solute : 17500 mg
5.
stock solution : 10 M HCl
we need : 500 ml of 5 mM HCl .
thus moles of HCl needed : 5*10-3 mol/L * 0.5 L = 2.5*10-3 mol
volume of stock solution needed : 2.5*10-3 mol / 10 mol/L = 2.5*10-4 L = 0.25 mL
Volume of d-H2O : 499.75 mL
6.
50 ng DNA in 5uL :
Thus conc. of this solution : 50 ng/ 5 uL = 50*10-9 g / 5*10-6 L = 0.01 g/L or 10 ng/uL
Original stock solution 350 ng/ul : 35 time dilution.
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