A proton is fired from far away toward the nucleus of a mercury atom. Mercury is...
A proton is fired from far away toward the nucleus of a mercury
atom. Mercury is element number 80, and the diameter of the nucleus
is 14.0 fm.
If the proton is fired at a speed of 4.6×107 m/s , what is its
closest approach to the surface of the nucleus? Assume the nucleus
remains at rest.
Homework Answers
let r be the distance in closest approach
initial K.E = P.E
0.5 * mp * v^2 = (k *q1 * q2 / r)
(0.5 * 1.67 * 10^-27 * sqr(4.6* 10^7)) = (9*10^9 * 1.6*10^-19 * 80 * 1.6*10^-19 / r )
therefore r = 1.0432 * 10^-12 m
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A proton is fired from far away toward the nucleus of a mercury
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