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The graph shows the component of a force acting on an object, in newtons, versus the position of the object, in meters. Find the work done by the force over the specified intervals of displacement:The graph shows the component of a force acting on an object, in newtons, versus the position of the object, in meters. Find the work done by the force over the specified intervals of displacement: a) x;=0.0 m, xf = 4.7 m; 10 Number Wー 4 b) x = 6.0 m, x-12.7 m: Fx (N) o Number 2 W= c) xi = 14 m, x,-16.9 m; 0 1 2 34 5 6789 10 11 12 13 14 15 16 17 18 19 20 Number X (m) W=

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Fo 125-65-lo. 2ゴ CÔO l- au↑w.tu.

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