The graph shows the component of a force acting on an object, in newtons, versus the...
The graph shows the component of a force acting on an object, in newtons, versus the position of the object, in meters. Find the work done by the force over the specified intervals of displacement: The graph shows the component of a force acting on an object, in newtons, versus the position of the object, in meters. Find the work done by the force over the specified intervals of displacement: a) x;=0.0 m, xf = 4.7 m; 10 Number Wー...
The graph shows the component of a force acting on an object, in newtons, versus the position of the object, in meters. Find the work done by the force over the specified intervals of displacement:
Please answer to the best of your ability with the information provided. The graph shows the component of a force acting on an object, in Newtons, versus the position of the object, in centimeters. Find the work done by the force over the 30 cm xf = 90 cm F. (N) 0 1 2 3 $ 6 9 10 11 12 13 14 15 16 17 18 19 20 (cm) 1.0.24J 0.0 36 J C048J
Question 6 of 29 > The graph shows the force acting on an object as a function of the position of the object. For each numbered interval given, find the work W done on the object. 1) from x = 0 m to x = 2.10 m F (N) W = 1 2 3 4 5 6 7 Tx(m) 10 8 9 2) from x = 3.00 m to x = 5.50 m W2 = 3) from x = 7.00...
The graph shows the force acting on an object as a function of the position of the object. For each numbered interval given, find the work W, done on the object. 1)from x = 0 m to x = 2.10m 0 x(m) 8 9 10 -2 2) from x 3.00 m to x 5.50 m -6 W2 = 3) from x = 7.00 m to x = 8.70 m
A force moves an object in the direction of the force. The graph shows the force versus the object's position (a) Find the work done when the object moves from 0 to 2.0 m. (b) If the mass of this object is 1.5 Kg and it started from rest find the final velocity at 2.0 m.
The force acting on an object is given by Fy = (4x – 8) N, where x is in meters. (a) Choose the plot that best describes the force versus x from x = 0 to x = 3.00 m. F, (N) 20+ Fx (N) 20+ 104 IL x (m) 0,5 10 15 20 25 30 0,5 Lux (m) 10 15 20 25 30 -207 -20+ Fx (N) F(N) 20+ 207 101 x (m) Lux (m) 10 15 20 25...
3. A 0.5 kg object moves along a straight line. The net force acting on the object varies with its displacement as shown by the graph on the next page. The object starts from rest at x = 0 and travels a total distance of 20 m. 5 4 Force 2 6 8 10 1214 16 18 2022 Displacement (m) each of the following: (a) the acceleration of the object at x-6 m (b) the time needed for the object...
The vx-versus-time graph for a 1.8-kg object is shown in (Figure 1) . A single force acts on the object, and the force has only an x component. Part A What is Fx at t=0.50s? Express your answer to two significant figures and include appropriate units. Part B What is Fx at t=2.0s? Express your answer to two significant figures and include appropriate units. Part C What is Fx at t=4.0s? Express your answer to two significant figures and include...
A 2.55-kg object constrained to move along the x-axis is subjected to a time-varying force as shown on the graph below. Find the change in the object\'s velocity over the specified time intervals. A 2.55-kg object constrained to move along the x-axis is subjected to a time-varying force as shown on the graph Find the change in the a) Between 0 s and t4.23 s s velocity over the specified time intervals. Force vs. Time Number 15 A- 199 12...