Question

3. A 0.5 kg object moves along a straight line. The net force acting on the object varies with its displacement as shown by the graph on the next page. The object starts from rest at x = 0 and travels a total distance of 20 m. 5 4 Force 2 6 8 10 1214 16 18 2022 Displacement (m) each of the following: (a) the acceleration of the object at x-6 m (b) the time needed for the object to move its first 16 m (c) the net work done in displacing the object 20 m (d) the objects speed at x 20 m

0 0
Add a comment Improve this question Transcribed image text
Answer #1

b From Kinenatie quahin ら e) Avea under the Cuwe The nef wove done ny 2(4 LJ) -116.9 m/s

Add a comment
Know the answer?
Add Answer to:
3. A 0.5 kg object moves along a straight line. The net force acting on the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (Figure 1) shows the force acting on a 4.5 kg object as it moves along the...

    (Figure 1) shows the force acting on a 4.5 kg object as it moves along the r-axis. The object is at rest at the origin at 10s. What are its acceleration and velocity at t = 6s? Part A What is its acceleration at 6 s? Express your answer with the appropriate units. a Value Units Submit Request Answer Figure < 1 of 1 > Part B What is its veloocity at 6 s? Express your answer with the appropriate...

  • If a single constant force acts on an object that moves on a straight line

    If a single constant force acts on an object that moves on a straight line, the object's velocity is a linear function of time. The equation v=vi + at gives its velocity v as a function of time, where a is its constant acceleration. What if velocity is instead a linear function of position? Assume that as a particular object moves through a resistive medium, its speed decreases as described by the equation v = vi-vx, where k is a...

  • For a moving object, the force acting on the object varies directly with the object's acceleration....

    For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 28 N acts on a certain object, the acceleration of the object is 7 m/s . If the force is changed to 36 N, what will be the acceleration of the object? ola x X 6 ?

  • 3. The net force acting on a 2.0-kg particle as it is pushed along a horizontal...

    3. The net force acting on a 2.0-kg particle as it is pushed along a horizontal floor (considered along the positive x-axis) varies as shown on the given chart. The velocity of the object at x = 1 m is 3.0 m/s. (a) Find the total work done on the crate along F (N) the floor from x-0 to x-3 m. (b) Estimate the final velocity of the particle at x 3 m. 0 r (m) [(a) -2J; (b) 1.73...

  • A 2.0 kg object moves along the x-axis under the influence of an unknown force. Its...

    A 2.0 kg object moves along the x-axis under the influence of an unknown force. Its potential energy due to the force is U(x) = ax4 + bx2 , where a = 2.5 J/m4 and b = 12 J/m2 a) What is the force on the object when x = 0.5 m? b) If the object is released from rest at x = 0.5 m, what is its velocity when it crosses the origin?

  • A force acting on an object moving along the x axis is given by Fx =...

    A force acting on an object moving along the x axis is given by Fx = (3.0 – x) N where x is in m. Calculate the work done by the force when the object moves from x = 1.0m to x = 3.0m.

  • A force acting on an object moving along the x axis is given by Fx =...

    A force acting on an object moving along the x axis is given by Fx = (14x - 3.0x2) N where x is in m. How much work is done by this force as the object moves from x = -1 m to x = +2 m? +12J +42J +32J +28J -12J

  • Net 15.04 4. An object of mass M = 12.0 kg is moving in the +...

    Net 15.04 4. An object of mass M = 12.0 kg is moving in the + x direction. As it passes the point x = 0, its speed is 5.00 m/s. The graph shows the net force, which points in the + x direction, that is acting on the object. Calculate: a) The net work done on the object as it moves from x=0 to X = 5.00 m b) The speed of the object as it passes the point...

  • 5. (15 pts] A force acting on an object is proportional to the square root of...

    5. (15 pts] A force acting on an object is proportional to the square root of the distance the object moves. The equation for the distance r is: 19 = kyr, for some constant k. The object starts at t=0 with position r = 0 and velocity v = 0. The object moves four meters in the first second. That is, r(t = 1) = 4. (a) Find the object's velocity as a function of position, v(r). (b) Find the...

  • A 100 kg object experience a net force of (120i+140j) N, it is initially at rest,...

    A 100 kg object experience a net force of (120i+140j) N, it is initially at rest, and its position starts at the origin. What is the object's acceleration? After 4 seconds, what is the velocity of this object? What is its position after 5 seconds (x,y), distance from the origin and angle defined from the positive x-axis?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT