3. A 0.5 kg object moves along a straight line. The net force acting on the...
(Figure 1) shows the force acting on a 4.5 kg object as it moves along the r-axis. The object is at rest at the origin at 10s. What are its acceleration and velocity at t = 6s? Part A What is its acceleration at 6 s? Express your answer with the appropriate units. a Value Units Submit Request Answer Figure < 1 of 1 > Part B What is its veloocity at 6 s? Express your answer with the appropriate...
If a single constant force acts on an object that moves on a straight line, the object's velocity is a linear function of time. The equation v=vi + at gives its velocity v as a function of time, where a is its constant acceleration. What if velocity is instead a linear function of position? Assume that as a particular object moves through a resistive medium, its speed decreases as described by the equation v = vi-vx, where k is a...
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 28 N acts on a certain object, the acceleration of the object is 7 m/s . If the force is changed to 36 N, what will be the acceleration of the object? ola x X 6 ?
3. The net force acting on a 2.0-kg particle as it is pushed along a horizontal floor (considered along the positive x-axis) varies as shown on the given chart. The velocity of the object at x = 1 m is 3.0 m/s. (a) Find the total work done on the crate along F (N) the floor from x-0 to x-3 m. (b) Estimate the final velocity of the particle at x 3 m. 0 r (m) [(a) -2J; (b) 1.73...
A 2.0 kg object moves along the x-axis under the influence of an unknown force. Its potential energy due to the force is U(x) = ax4 + bx2 , where a = 2.5 J/m4 and b = 12 J/m2 a) What is the force on the object when x = 0.5 m? b) If the object is released from rest at x = 0.5 m, what is its velocity when it crosses the origin?
A force acting on an object moving along the x axis is given by Fx = (3.0 – x) N where x is in m. Calculate the work done by the force when the object moves from x = 1.0m to x = 3.0m.
A force acting on an object moving along the x axis is given by Fx = (14x - 3.0x2) N where x is in m. How much work is done by this force as the object moves from x = -1 m to x = +2 m? +12J +42J +32J +28J -12J
Net 15.04 4. An object of mass M = 12.0 kg is moving in the + x direction. As it passes the point x = 0, its speed is 5.00 m/s. The graph shows the net force, which points in the + x direction, that is acting on the object. Calculate: a) The net work done on the object as it moves from x=0 to X = 5.00 m b) The speed of the object as it passes the point...
5. (15 pts] A force acting on an object is proportional to the square root of the distance the object moves. The equation for the distance r is: 19 = kyr, for some constant k. The object starts at t=0 with position r = 0 and velocity v = 0. The object moves four meters in the first second. That is, r(t = 1) = 4. (a) Find the object's velocity as a function of position, v(r). (b) Find the...
A 100 kg object experience a net force of (120i+140j) N, it is initially at rest, and its position starts at the origin. What is the object's acceleration? After 4 seconds, what is the velocity of this object? What is its position after 5 seconds (x,y), distance from the origin and angle defined from the positive x-axis?