Question

A thin rigid rod of MM = 1.6 kg and L = 3.2 m rotates at the angular speed ω = 5 rev/s around the rotation axis which is at d = 0.1 m from the center of the mass of the rod, as shown. Note that ICM = ML^2/12 for a thin rod.
A. Calculate the moment of inertia I of the rod for the rotation axis.
B. What is the rotational kinetic energy of the thin rod?



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Answer #1

Q TA Center I = E Io Moment of Enestia I comt md2 ML? + Md? 1.6 x (3-2) + 1.6X(0:1) I a 1.26+ 0.016 = 1.276 kgm2(3 Rotational kmens energy KE.a 12w2 Wa srevils a 7 x 1.276X (52 k.f. = 15.955 2

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