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(1 point) A spring-mass system with a 5-kg mass and a damping constant 8-N sec/m can be held stretched 0.5 meters beyond its

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F = kx 2.5 = K (0.5) (k = 51 => c2-4mk = (8)2-4(5)(5) = -36 The auxiliary equation is - md²y + Cdy tkyo doch doch y = - +102-

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