What is the mass of
insoluble silver bromide (187.77 g/mol) produced from 2.96 g of iron(III) bromide
(295.55 g/mol) and aqueous silver nitrate?
FeBr3(s) + AgNO3(aq) → AgBr(s) + Fe(NO3)3(aq)
What is the mass of insoluble silver bromide (187.77 g/mol) produced from 2.96 g of iron(III)...
Question 71. If 25.0 mL of 0.150 M aluminum bromide reacts with 15.0 mL of 0.200 M silver nitrate, what mass of silver bromide is produced? AgBr ()+ AI(NO3)3 (aq) AIBr3 (aq)+AgNO3 (aq) a) 2.11 x 104 g b) 2.11 g c) 5.63 x 104 g d) 0.563 g e) none of the above Question 72 What is the molarity of aluminum ions in the above question before the reaction has taken place? a) 0.150 M A13 b) 0.350 M...
Question 1 According to the following reaction, what mass of silver nitrate would be required to react with 0.500 grams of potassium chloride? AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq) options 2.68 g 0.500 g 85.0 g 170 g 1.14 g Question 2 Consider the reaction: Na2CO3 (aq)+ 2 HCl (aq) --> 2 NaCl (aq) + CO2 (g) + H2O (l) If 43.41 g of sodium carbonate react completely, how many grams of HCl will be...
How many grams of silver bromide, AgBr, are produced if 15.0 mL of 0.350 M CaBr2(aq) completely react given the reaction: 2 AgNO3(aq) + CaBr2(aq) → Ca(NO3)2(aq) + 2 AgBr(s)
In the reaction of silver nitrate with calcium bromide (shown below), which species are the spectator ions? 2 AgNO3(aq) + CaBr2(aq) → 2 AgBr(s) + Ca(NO3)2(aq)
6. (16 points) Magnesium bromide reacts with silver nitrate to form silver bromide (solid) and magnesium sulfate (aq). A mixture of 50.0 8 of magnesium bromide (MM 184.1 g/mol) and 100 g of silver nitrate (MM- 169.9 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete, Do by ICE Method Type of reaction Double displacement 2015 MgBra (5) + 2 AgNO,(aq) > Mg(NO)2(aq)...
6. (16 points) Magnesium bromide reacts with silver nitrate to form silver bromide (solid) and magnesium sulfate (aq). A mixture of 50.0 g of magnesium bromide (MM - 184.1 g/mol) and 100 g of silver nitrate (MM- 169.9 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete, Do by ICE Method Type of reactionDouble displacement 2115 MgBra (s) 2 AgNO (aq) > Mg(NO3)2(aq)...
Silver nitrate, AgNOs, reacts with iron(III) chloride, FeCl3,to give silver chloride, AgCl, and iron(III) nitrate, Fe(NO3). A solution containing 18.0 g of AgNO, was mixed with a solution containing 32.4 g of FeCls. How many grams of which reactant remains after the reaction is over?
Given that 50.0 mL of 0.100 M magnesium bromide reacts with 13.9 mL of silver nitrate solution according to the unbalanced equation MgBr2 + AgNO3 = AgBr + Mg(NO3)2 (a) What is the molarity of the AgNO3 solution? (b) What is the mass of AgBr precipitate?
For the following reaction, 5.09 grams of iron(II) chloride are mixed with excess silver nitrate Assume that the percent yield of iron(II) nitrate is 93.4% Iron(II) chloride(aq) + silver nitrate(aq) iron(II) nitrate(aq) + silver chloride(s) What is the ideal yield of iron(II) nitrate? What is the actual yield of iron(II) nitrate? grams grams Submit ANSWER Retry Entire Group 2 more group attempts remaining The equation for this reaction is: FeCl2(aq) + 2 AgNO3(aq) - Fe(NO3)2(aq) + 2 AgCl(s)
A 2.018-g sample of a metal bromide. MBr2, is dissolved in water and treated with excess aqueous silver nitrate. The silver bromide (AgBr) that formed weighed 2.721 g. Calculate the atomic mass of Mand identify M. (molar mass of AgBr - 187.80 g/mol)