In the reaction of silver nitrate with calcium bromide (shown below), which species are the spectator ions?
2 AgNO3(aq) + CaBr2(aq) → 2 AgBr(s) + Ca(NO3)2(aq)
In the given reaction, calcium ion (Ca2+) and nitrate ion are spectator ions because they remain unchanged during the reaction i.e. in ionic form whereas Ag+ and Br- change their identity and do formation of precipitate..
In the reaction of silver nitrate with calcium bromide (shown below), which species are the spectator...
How many grams of silver bromide, AgBr, are produced if 15.0 mL of 0.350 M CaBr2(aq) completely react given the reaction: 2 AgNO3(aq) + CaBr2(aq) → Ca(NO3)2(aq) + 2 AgBr(s)
What are the spectator ions in the reaction of silver nitrate with sodium bromide?
When solutions of calcium chloride and silver nitrate are mixed, silver chloride and calcium nitrate are produced. CaCl2 + 2 AgNO3 --> 2 AgCl + Ca(NO3)2 How many grams of silver chloride are formed when 59 grams of AgNO3 react with excess calcium chloride? Please include units in your answer and round to 2 decimal places. Answer: Check Next page
Question 71. If 25.0 mL of 0.150 M aluminum bromide reacts with 15.0 mL of 0.200 M silver nitrate, what mass of silver bromide is produced? AgBr ()+ AI(NO3)3 (aq) AIBr3 (aq)+AgNO3 (aq) a) 2.11 x 104 g b) 2.11 g c) 5.63 x 104 g d) 0.563 g e) none of the above Question 72 What is the molarity of aluminum ions in the above question before the reaction has taken place? a) 0.150 M A13 b) 0.350 M...
What is the mass of insoluble silver bromide (187.77 g/mol) produced from 2.96 g of iron(III) bromide (295.55 g/mol) and aqueous silver nitrate? FeBr3(s) + AgNO3(aq) → AgBr(s) + Fe(NO3)3(aq)
Given that 50.0 mL of 0.100 M magnesium bromide reacts with 13.9 mL of silver nitrate solution according to the unbalanced equation MgBr2 + AgNO3 = AgBr + Mg(NO3)2 (a) What is the molarity of the AgNO3 solution? (b) What is the mass of AgBr precipitate?
When solutions of silver nitrate and calcium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq)+CaCl2(aq)→2AgCl(s)+Ca(NO3)2(aq) Part A: What mass of silver chloride can be produced from 1.07 L of a 0.225 M solution of silver nitrate? Part B: The reaction described in Part A required 3.13 L of calcium chloride. What is the concentration of this calcium chloride solution?
6. (16 points) Magnesium bromide reacts with silver nitrate to form silver bromide (solid) and magnesium sulfate (aq). A mixture of 50.0 8 of magnesium bromide (MM 184.1 g/mol) and 100 g of silver nitrate (MM- 169.9 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete, Do by ICE Method Type of reaction Double displacement 2015 MgBra (5) + 2 AgNO,(aq) > Mg(NO)2(aq)...
Question 1 According to the following reaction, what mass of silver nitrate would be required to react with 0.500 grams of potassium chloride? AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq) options 2.68 g 0.500 g 85.0 g 170 g 1.14 g Question 2 Consider the reaction: Na2CO3 (aq)+ 2 HCl (aq) --> 2 NaCl (aq) + CO2 (g) + H2O (l) If 43.41 g of sodium carbonate react completely, how many grams of HCl will be...
When solutions of silver nitrate and calcium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq)+CaCl2(aq)→2AgCl(s)+Ca(NO3)2(aq) Part A What mass of silver chloride can be produced from 1.91 L of a 0.235 M solution of silver nitrate? Express your answer with the appropriate units. Part B The reaction described in Part A required 3.05 L of calcium chloride. What is the concentration of this calcium chloride solution? Express your answer with the appropriate units.