11. Two white-flowered strains of the sweet pea (Lathyrus odoratus) were crossed producing an F1 with...
11.
Two white-flowered strains of the sweet pea (Lathyrus odoratus) were crossed producing an F1 with only purple flowers. Random crossings among the F1 produced 97 progeny plants: 54 with purple flowers and 43 with white flowers.
a) What is the phenotypic ratio of the F2 generation?
b) What are the probable genotypes of the parental generation?
c) How would you explain biochemically the relationship between purple and white flowers?
PLEASE SHOW WORK THANK YOU
Homework Answers
Answer:
a). The phenotypic ratio of the F2 generation= 9:7
b). The probable genotypes of the parental generations are AAbb & aaaBB
c).
54 : 43 = 9:7
The 9:7 ratio is observed in duplicate recessive epistasis. When there is a recessive allele masking the expression of dominant alleles at two loci, this is known as duplicate recessive epistasis.
A_B_ = Purple
A_bb or aaB_ or aabb = White
White (aaBB) x White (AAbb)---Parents
AaBb (purple)------------------------F1
AaBb x AaBb------------------------Self cross
|
AB |
Ab |
aB |
ab |
|
|
AB |
AABB (purple) |
AABb (purple) |
AaBB (purple) |
AaBb (purple) |
|
Ab |
AABb (purple) |
AAbb (white) |
AaBb (purple) |
Aabb (white) |
|
aB |
AaBB (purple) |
AaBb (purple) |
aaBB (white) |
aaBb (white) |
|
ab |
AaBb (purple) |
Aabb (white) |
aaBb (white) |
aabb (white) |
Purple = 9
White = 7
Therefore, phenotypic ratio or the F2 generation= 9:7
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