Solution:
Key points:
By the observations we can say the given circuit can work as a LOW PASS FILTER .
Because at lower frequency capacitor offer infinite resistance hence it will be open circuited so the Output voltage will be same as the input ( Vo = Vin ) so it signifies it is passing all the lower frequencies.
For higher values of frequency capacitor will be short circuited hence output voltage will be zero so Vout = 0V . Hence its attenuating the higher frequencies hence its a LOW PASS FILTER.
Transfer Function (H(S)) = Vo(S) / Vi (S).
Vo(S) = H(S) × Vi(S) . By the above analysis we can get Vo(S) .
Further by applying inverse Laplace transform we get Vo(t).
Question 4. Refer to the circuit of Figure 4. R 802 50 uF с vi(t) v.(t)...
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