Question

I The following data were obtained from a study comparing 3 treatment conditions, with 5 participants in each treatment condition. Assuming the statistic reported below is significant at .05 conduct Tukey post hoc tests for all pairwise comparisons. Treatment 1 Treatment 2 Treatment 3 Means MS SS 70 F=10.51 Source Between Treatments Within Treatments Total 3.33 110 :

Answer 1

Tukey's post Hoc test MSE T = Q & (t, ort) v mi a 2 lt, n-t) - studentized range distribution based on t, (n-t) df. t = number of treatments - 3 - total sample size = 3x5=15 MSE - Mean square Eroor = 3.33 ni- sample size of the treatment group with the smallest number of observations = 5 1.33 VS T = 20.05, (3, 15-3) s - 20.05, (3,12) ✓ 3.33 = 3.773 /3:33 - 3.079 Absolute values of paired Mean as follows I 18-72 1 = 11-5)=4 7 3:079 [difference betwan 1 62 is signifiant at a=005]. 118, -731= 11-61 =5>3:079 [difference between I and 3 is significant atdoor 1182-731= 15-67-183.079 [ difference between 2 and 3 is not significant at a-doc