Question

A pendulum with a bob of mass 0.400 kg ball is released from an angle of...

A pendulum with a bob of mass 0.400 kg ball is released from an angle of 10.00°. You find that the time for 10 oscillations is 12.0 s. What is the length of the string?

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Answer #1

T = 1.2 second

1.2 second = 2\pi\sqrtl/g

1.2x1.2 = 4\pi2(L/g)

L = 1.44x9.8/40

L= 0.3528 m

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