QUESTION 3 You have 65.0 mL of a 1.25 M solution of Na2CO3(aq). You also have...

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Question 3 Moles of Ag* = 5.68M 135mLx obb, = 0.7668 mol Moles of Cro - =1. 25 MX 65.0 mL X- 1000 mL = 0.08125 mol 2 Ag+ (aq)

Question 4 2Al(s)+3C12(g) → 2 AICI: Oxidation half reaction 2Al(s) +2A1+ + 6€ Reduction half reaction 3C1(g)+61 +601 Overall

Answer 2

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