Question

Figure 3 shows an emitter and receiver of waves mo

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Answer #1

This is a doppler effect problem where receiver is moving and emitter is moving relative to target with velocity v0.

So

f_r=f_e\left(\frac{c+v_0}{c-v_0}\right)\\ \implies f_r c-f_rv_0=f_ec+f_ev_0\\ \implies \frac{(f_r-f_e)c}{f_r+f_e}=v_0

\frac{(f_r-f_e)c}{f_r+f_e}=v_0\\ \implies \frac{(22.2-18)\times 10^3\times 343}{(22.2+18)\times 10^3}=v_0\\ \implies 35.84/s=v_0

Generally wind affects measurement.

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