Worldwide, approximately 1 in 17000 people have the genetically inherited condition of albinism. The albino gene...
Worldwide, approximately 1 in 17000 people have the genetically inherited condition of albinism. The albino gene is recessive. Using the Hardy-Weinberg equilibrium, calculate the frequency of the albino gene and of carriers of the albinism allele.
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Worldwide, approximately 1 in 17000 people have the genetically
inherited condition of albinism. The albino gene...
The incidence of Tay Sachs, an autosomal recessive genetic disorder, is approximately 1 in 3,500 in...
The incidence of Tay Sachs, an autosomal recessive genetic
disorder, is approximately 1 in 3,500 in a certain population of
Ashkenazi Jews. Assuming Hardy-Weinberg equilibrium, what is the
frequency of carriers for the Tay Sachs allele in this
population?
The incidence of Tay Sachs, an autosomal recessive genetic disorder, is approximately 1 in 3,500 in a certain population of Ashkenazi Jews. Assuming Hardy-Weinberg equilibrium, what is the frequency of carriers for the Tay Sachs allele in this population? OOO 98.5%...
In humans, normal pigmentation is due to a dominant gene A. Albinism is due to a...
In humans, normal pigmentation is due to a dominant gene A. Albinism is due to a recessive allele a. A normal man marries an albino woman and their first child is albino. What are the genotypes of all three people? If they have more children what would their pigmentation be like?
Fictional scenario: Individuals with green hair have the presence of the dominant gene "Z" and people...
Fictional scenario: Individuals with green hair have the presence of the dominant gene "Z" and people with purple hair are homozygous for the recessive allele “z”. There were 200 students in a classroom who were surveyed for their hair color and 155 people had green hair whereas 45 people had purple hair. Use the information to answer the next set of questions. Show your work for credit. 1) What are the variables for a recessive allele? A dominant allele? Homozygous...
In humans, sickle-cell anemia (HBBSHBBS) is caused by the recessive condition of an autosomal gene with...
In humans, sickle-cell anemia (HBBSHBBS) is caused by the recessive condition of an autosomal gene with two alleles: HBBA (wild-type) and HBBS (sickle-cell mutation). In one population, the frequency of individuals who do not suffer from sickle-cell anemia (HBBAHBBA and HBBAHBBS) is 0.9964. Assuming the population is in Hardy-Weinberg equilibrium, what is the frequency of the HBBS allele?
In Europe, approximately 4% of people are red-haired, mostly due to a recessive mutation in the...
In Europe, approximately 4% of people are red-haired, mostly due to a recessive mutation in the melanocortin 1 receptor (MC1R). If the population is in Hardy-Weinberg equilibrium, what is the likelihood that a non-redheaded European is a carrier for the MC1Rr allele? (For the purpose of this problem, assume all redheads and carriers are mutant for the same MC1R allele). A Option A: 22% B Option B: 33% C Option C: 11% D Option D: 44%
Suppose that in a population the frequency of a particular recessive condition is 1/800. Assume the...
Suppose that in a population the frequency of a particular recessive condition is 1/800. Assume the presence of only a dominant allele (A) and a recessive allele (a) in the population and that the population is at Hardy-Weinberg equilibrium. What is the frequency of the recessive allele that causes the condition? A. 0.000625 B. 0.0025 C. 0.35 D.0.05 E. 0.025
9. In humans, normal pigmentation is due to a dominant gene (C), albinism to it's recessive...
9. In humans, normal pigmentation is due to a dominant gene (C), albinism to it's recessive allele (c). A normal pigmented man has children with an albino woman. Their first child is an albino. What are the genotypes of each of these three people? IF THEY HAD MORE CHILDREN, WHAT WOULD BE THE GENOTYPIC AND PHENOTYPIC RATIO PROBABILITIES? EXPLAIN YOU REASONING!! SHOW YOUR WORK USING A PUNNETT SQUARE!! Wor m mentation(c)
2.3 Problem 3 The Hardy-Weinberg equation is useful for predicting the percent of a hu- man...
2.3 Problem 3 The Hardy-Weinberg equation is useful for predicting the percent of a hu- man population that may be heterozygous carriers of recessive alleles for certain genetic diseases. Phenylketonuria (PKU) is a human metabolic dis- order that results in mental retardation if it is untreated in infancy. In the United States, one out of approximately 10.000 babies is born with the disor- der. Approximately what percent of the population are heterozygous carriers of the recessive PKU allele? If you...
Albinism is an autosomal recessive trait in humans. Assume that there are 200 albinos ( aa)...
Albinism is an autosomal recessive trait in humans. Assume that there are 200 albinos ( aa) in a population of 1 million. How many individuals would be expected to be carriers (Aa) under equilibrium conditions? Answer Choices: A.200 B.400 C.10,000 D.980,100 E.400,000 Please show your work using the Hardy Weinberg equation!
Homework for lab 12: The allele for color blindness is inherited as a recessive allele. Using...
Homework for lab 12: The allele for color blindness is inherited as a recessive allele. Using letter B (normal allele) and b (color blind allele) Answer the questions below: 1. What genotype will be normal 2. What genotype will have color blindness 3. Color blindness is found in about 8% of the population. Using the Hardy-Weinberg formula, determine the frequency of a. Homozygote dominant b. Heterozygote c. Homozygote recessive
The incidence of Tay Sachs, an autosomal recessive genetic
disorder, is approximately 1 in 3,500 in a certain population of
Ashkenazi Jews. Assuming Hardy-Weinberg equilibrium, what is the
frequency of carriers for the Tay Sachs allele in this
population?
The incidence of Tay Sachs, an autosomal recessive genetic disorder, is approximately 1 in 3,500 in a certain population of Ashkenazi Jews. Assuming Hardy-Weinberg equilibrium, what is the frequency of carriers for the Tay Sachs allele in this population? OOO 98.5%...
Fictional scenario: Individuals with green hair have the presence of the dominant gene "Z" and people with purple hair are homozygous for the recessive allele “z”. There were 200 students in a classroom who were surveyed for their hair color and 155 people had green hair whereas 45 people had purple hair. Use the information to answer the next set of questions. Show your work for credit. 1) What are the variables for a recessive allele? A dominant allele? Homozygous...
Suppose that in a population the frequency of a particular recessive condition is 1/800. Assume the presence of only a dominant allele (A) and a recessive allele (a) in the population and that the population is at Hardy-Weinberg equilibrium. What is the frequency of the recessive allele that causes the condition? A. 0.000625 B. 0.0025 C. 0.35 D.0.05 E. 0.025
9. In humans, normal pigmentation is due to a dominant gene (C), albinism to it's recessive allele (c). A normal pigmented man has children with an albino woman. Their first child is an albino. What are the genotypes of each of these three people? IF THEY HAD MORE CHILDREN, WHAT WOULD BE THE GENOTYPIC AND PHENOTYPIC RATIO PROBABILITIES? EXPLAIN YOU REASONING!! SHOW YOUR WORK USING A PUNNETT SQUARE!! Wor m mentation(c)
2.3 Problem 3 The Hardy-Weinberg equation is useful for predicting the percent of a hu- man population that may be heterozygous carriers of recessive alleles for certain genetic diseases. Phenylketonuria (PKU) is a human metabolic dis- order that results in mental retardation if it is untreated in infancy. In the United States, one out of approximately 10.000 babies is born with the disor- der. Approximately what percent of the population are heterozygous carriers of the recessive PKU allele? If you...
Homework for lab 12: The allele for color blindness is inherited as a recessive allele. Using letter B (normal allele) and b (color blind allele) Answer the questions below: 1. What genotype will be normal 2. What genotype will have color blindness 3. Color blindness is found in about 8% of the population. Using the Hardy-Weinberg formula, determine the frequency of a. Homozygote dominant b. Heterozygote c. Homozygote recessive
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