as shown in the plotted L-J potentials for Xe-Xe and Ar-Ar ,
Xe-Xe potential has deeper minimum because this is V vs r graph and its derivative ( dv/dr i.e. slope ) if concave down/ negative slope -attractive if concave up/positive slope -repulsive in nature
in this Xe-Xe have deeper minimum than Ar-Ar because
Xe-Xe have more vander waals radius and
repulsion exponent for xenon (12) is higher than Ar(9) as shown below-
Ar -9
Xe- 12
2. The ε and σ values for Lennard-Jones potential of xenon are found to be 1.77...
Using this table determine the
van der Waal radius for Ar. Then use this radius to determine the
fraction of volume occupied by 1 mol of argon at 25C and 1 atm.
Table 17.2 Lennard-Jones Parameters for Atoms and Molecules Particle e/kJ mol-1 o/Å 0.997 1.77 0.307 0.765 0.943 3.40 4.10 2.93 3.92 3.65 4.33 3.82 1.65 1.23 2.02 C6H6 8.60
4) For Ne, the parameters of the Lennard-Jones 6-12 potential are ε/Kg-35.6 K and σ-275 pm. Plot V(r) in J/mol versus r from 250-800 pm. Calculate the distance rm where dV/dr-0.
14-5. Using Eqs. (14-14) and (14-17), calculate the van der Waals constants a and b for nitrogen. For u(r), assume a Lennard-Jones 6-12 potential with ε and σ given in Table 12-3. Compare these calculated values to the experimentally determined values, a 1.39 x 106 cm atm/mole and b-39.1 cm/mole. Such poor agreement is quite typical, simply indi- cating the inadequacy of the van der Waals equation. 14-2 THE VAN DER WAALS EQUATION We start with Eq. (14-3), and take...