NaCN(aq) -------------> Na^+ (aq) + CN^- (aq)
1.8*10^-3 M 1.8*10^-3M
Kb = Kw/Ka
= 1*10^-14/(4.9*10^-10) = 2.04*10^-5
CN^- (aq) + H2O(l) --------------> HCN(aq) + OH^- (aq)
I 1.8*10^-3 0 0
C -x +x +x
E 1.8*10^-3 +x +x
Kb = [HCN][OH^-]/[CN^-]
2.04*10^-5 = x*x/(1.8*10^-3)
2.04*10^-5 *(1.8*10^-3) = x^2
x = 0.00019
[OH^-] = x = 0.00019M
POH = -log[OH^-]
= -log0.00019
= 3.72
PH = 14-POH
= 14-3.72
= 10.28
[CN^-] = 1.8*10^-3-x
= 1.8*10^-3-0.00019 = 0.00161M
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