Given
the area of the caoacitor is A = 4.2*6.7 cm2 = 0.2814 m2
separation of the plates is d = 0.3*10^-6 m
we know that capacitance C = epsilon not A /D
a)
C =
8.854*0^-12*0.2814 /(0.3*10^-6) F
C = 8.305052*10^-6 F
b) from the relation Q = C*V
= 8.305052*10^-6*15.5 C
=
0.000128728306 C
= 0.000128728306
mC
c)
dielectric constant of water is k = 80.4
the space between the plates is filled with
water of k = 80.4
capacitance of the capacitor increases by k times
C' =
k*C
C' = 80.4*0.000128728306*10^-3 F
C' = 10.3497558024*10^-6
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