Question

Q1) (Total duration including uploading process to the Blackboard: 30 minutes) A full-wave rectifier is to be designed using the center-tapped transformer configuration. The peak output voltage is to be 140, the nominal load current is to be 0.65A. The ripple voltage is to be limited to 2%. Assumne the tas-on voltage for the diodes is Vy = 0.7V . The input signal is given as v; = 120V2sin[21(60)t] V. a) Sketch the circuit b) Find the transformer turns ratio. b) Determine the minimum value of capacitor required. c) Sketch the input signal v, versus output signal v, characteristics including all the critical values on the plot.

Answer 1

VE=12082 sin Carl C6o) t] v vr-0.7 Vo = 14 V Vs = 14.72 NI 120 V Ž 14. transformation ratio is R= VO 4 Vo 0.65 = 11:54 11.54 - 21.53852 Ripple Coltage limited to 2% Vr = 2% Vm = 20% x 14 -0.28 our- Vm 2 RCF 14 2% 21.5385 X 60 X 0.28 C =0.01934 F minimum value of capacitor is o.01934 Farad

Transformation ratio is 11.54,load resistance is 21.5385 ohm, capacitor value is 0.01934 farad.

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