Question

Suppose that 28 g of each substance is initially at 26.0 ∘C.​

Part A

What is the final temperature of gold upon absorbing 2.40 kJ of heat?

Express your answer using two significant figures.

Part B

What is the final temperature of silver upon absorbing 2.40 kJ of heat?

Express your answer using two significant figures.

Part C

What is the final temperature of aluminum upon absorbing 2.40 kJ of heat?

Express your answer using two significant figures.

Part D

What is the final temperature of water upon absorbing 2.40 kJ of heat?

Express your answer using two significant figures.

Answer 1

Part A) Let final temperature be Tf

heat = q = mCpdT

2.40 x 1000 = 28 x 0.129 x (Tf - 26)

Final temperature Tf = 690.45 oC

Part B) Final temperature of silver

2.40 x 1000 = 28 x 0.233 x (Tf - 26)

Final temperature Tf = 393.67 oC

Part C) Final temperature of Aluminum

2.40 x 1000 = 28 x 0.9 x (Tf - 26)

Final temperature Tf = 121.24 oC

Part D) Final temperature fo water

2.40 x 1000 = 28 x 4.18 x (Tf - 26)

Final temperature Tf = 46.50 oC