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Please completely answer the whole problem showing all work. Thank you.
Problem #5: Determining perpendicular distance between a line and a point. Line MN has a bearing S15°0724 E. The length of
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L (490.61, 741-25. 706.18) Im ( 368.54, pow N (2 ) Given M( 368054, 706.181 bearing Angle mn = sis of 24. = 256-57 ft- M (36Now M (368.54,906-18 ) . N (435-43, 458.69 ) e 4 em of line mw :- 9-9, = 2 gl (x-x) 12-14 F06-18 I 458069 - (x - 368018) y- 7Now yer distance from point L on to line MN axitby, te LG 490.61,741.25) X, Y) Varth 3.699 x 490.61+ 741.25-2068.07 1 √3.699t

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