Homework Answers
Answer :-
(a) :- Here we have to find out the normal times in TMUs for these motion elements.
Here we know the individual motion element times are given as below.:
(1) W5P, Tn= 5(15.0) = 75.0 TMU
(2) B, Tn= 29.3 TMU
(3) R14B, Tn= 14.4 TMU
(4) G1A, Tn= 2.0 TMU
(5) AB, Tn= 31.9 TMU
(6) W5P, Tn= 5(15.0) = 75.0 TMU
(7) P1SSE, Tn= 9.1 TMU
(8) RL1, Tn= 2.0 TMU
Normal times in TMUs for these motion elements = 75.0+29.3+14.4+2.0+31.9+75.0+9.1+2.0
= 238.7 TMU
The normal times in TMUs for these motion elements = 238.7 TMU.
(b):- Here we have to find out the total time for this work element in sec.
to get total time in seconds, Normal times is multiplied by 0.036.
Total time in seconds = 238.7 * 0.036
= 8.5932 sec
Total time in seconds = 8.5932 sec.
Note:-
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