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Problem 2 The graph below shows the position (x) as a function of time (t) for a particle moving in one dimension x (m) 6 5 4

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Answer #1

a) Partical is at rest at the two intervals.

i) 0-4.5 sec and ii) 10-11 sec

since position is not changing both the times

b) velocity is negative at 4.5 sec to 8 sec because slope is negative

c) particle is decelerating from 4.5 sec to 8 sec since velocity is decreasing continuously .

d) velocity at t= 12s

v= slope of line = 5-3/12-11=2/1

=2m/s

e) velocity at t=8 is zero as slope is zero

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