A 20 mm diameter, 500 g cylinder-shaped drill is spun up clockwise, starting from rest, by...
A 20 mm diameter, 500 g cylinder-shaped drill is spun up clockwise, starting from rest, by an applied torque of -0.2 [N m], after 2 seconds.
a. What is the drill's angular speed?
b. Through what total angle has it spun?
Homework Answers
(a) moment of inertia of cylinder = 1/2mr^2 = 0.5*0.5kg*(0.01
m)^2 = 0.000025 kgm2
torque = Ia
a = angular acceleration = 0.2/0.000025 = 8000 rad/s2
w = at = 8000*2 = 16000 rad/s
(b) angle theta = 1/2at^2 = 0.5*8000*4 = 16000 radians
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