Sotion-
The reaction can be written as
HF + NaOH ----- NaF + H2O
Initial 2M 1M 0.672M
Final 1M 0 1.328M
Using the hessley henderbach equation we get
pH = pKa + log[F-/HF]
=> (4 - log(7.2)) + log(1.328/1)
=> 4 - log(7.2/1.328)
=> 4 - log(5.421686)
=> 3.26
very close to option B
w question will save this response. Question 4 Calculate the pH of a solution that is...
HELP! Exam tomorrow!! Calculate the pH of a solution that is 2.00 M HF, 1.00 M NaOH, and 0.500M NaF n 1.00 L of the solution. Ka for HF = 7.2 x 10-4) HF(aq) + OH-(aq)-->F-(aq) + H2O(l) Correct answer is 3.32 really need help with the set up!! How many moles of solid NaF would have to be added to 1.0 L of 1.90 M HF solution to achieve a buffer of pH 3.35? Assume there is no volume...
Calculate the pH of a solution that is 0.50 M in HF (Ka = 7.2 x10-4) and1.50 M in NaF. A. 10.56 B. 3.62 C. 3.44 D. 0.30 E. 3.14
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Question 8 (10 points) Calculate the pH of a solution made by mixing 100.0 mL of 0.644 MNH; with 100.0 ml. of 0.100 MHCI. (K for NH; = 1.8 x 10-) 9.99 4.01 8.52 9.26 none of these Question 9 (10 points) Calculate the pH of a solution that is 0.50 Min HF (K-72 x 10-) and 0.66 Min NaF 3.14 3.26 b BE
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