Question

this is my lab and my Professor said some of the date is incorrect.

Teacher stated E = 10x10^6 psi. my data shows slope =9.3974. I'm off by 10^6. please show correct calculation and graphs. not sure how to correct

RESULTS Given the following b=1 Inch h = 114 inch = 0.25 inch L = 10 inch --0.125inch a substituting the above values for I we The moment of inertia of the beam section is given by, I = poti - am -0.013 inch b (inch) 1 h (inch) 0.25 Table 1 L / C (inch) (inch) 10 0.125 Table 1-Dimensions (inch)^4 0.0013 For Case 1 The bending moment is given by the equation M = PxL M-0.22 x 10 =2.2 lb./inch _MxC_22x0.125 The bending stress is given by the equation Sp a = 211.2 lb./inch For all other 211 21h linch? For all other cases, the calculated results are shown in table 2. Where P is the load acting on the cantilever beam, the strain measured by the strain gauge (dimensionless). M is the bending moment and Sb is the bending stress. Average Modulus is 56.261/6. The average Modulus Eis 9.3768 Table 2 Data EM Modulus (lb) (YE) (lb inch) (lb/inch) 0.22 23 2.2 211.2 9.182608696 0.439 45 4 ,39 421.44 9.556363636 3 0.876 8 9.5 8.76 840.96 9.42741573 4 0.986 1 01 9 .86 946 56 9.182608696 5 121 123.5 1 12. 1 161.6 9.55733333 6 2087 21305 20.87 2003.52 9.35466667 56.261 Table 2- Results for Experiment Flexural Bending Stress should be read in microstrain

Answer 1

Given, stress and strain date micro strain gives reading *10° stress so (1 strain ME slope MPsi slope Stress strain Иe ) psi DE 211.2 23 9.18260846 421.44 45 9.556363636 840.96 89-5 19.42741373 To 946:56 11161.6 koo 3.52 1979 2608696 1235 14.5573333 21305 9.3546667 :. units of slope - 106 psi =M psi Equation of line is y=9.3974 2 -115514 je, stress - E - 9.3974 MBS strain :. Young's modulus = 9.3974 x10 "Psi

The mistake you were doing is not calculating the unit's of data modulus.

The unit's for it is Mpsi

So, your slope will come 9.3974 Mpsi.

I hope this will help you.