Homework Answers
Answer :) option E
According to Hardy Weinberg's principle, the sum of all genotype frequencies for a single locus should be one. In all populations, the addition of the number of individuals is 100 that is the same as the given population size (100). Therefore, genotype frequencies are cumulatively 1.
For example, Population 1:
Genotype frequency of AA, p2 = 36/100
Genotype frequency of AA = 0.36
Genotype frequency of Aa, 2pq = 48/100
Genotype frequency of Aa = 0.48
Genotype frequency of aa, q2 = 16/100
Genotype frequency of aa = 0.16
According to the Hardy Weinberg principle,
p2 + 2pq+ q2 = 1
0.36 + 0.48+ 0.16 = 1
That would be the same for all other populations because the population size of all populations is the same as 100.
Therefore, option E is correct.
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