Question

A gun is fired it, as shown in the f 6. 1 kok fwat rst on a thin horiontal sheet direcely aboe vertically into a m figure below If the bullet has a mass of 21.4 g and a speed of t- 300 m/s, how high will the block rise into the air after the bullet becomes embedded in it? 7. An 19.8 g rifle bullet traveling 221 m/s buries itself in a 3.76 kg pendulum hanging on a 2.84 m long string, which makes the pendulum swing upward in an arc. Determine the horizontal component of the pendulums displacement
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Answer #1

6.

4.58m/s

m=1.38kg, M=0.0214kg, v=300m/s, v1i=0m/s

Use law of conservation of linear momentum

Pf=Pf

m1v1i +m2v2i = m1v1f +m2v2f

m*v1i +M*v = (m1+m2)*vcommon

1.38*0+0.0214*300 = (1.38+0.0214)*vcommon

vcommon= 4.58m/s

This is initial velocity of block+bullet in vertical direction

Thus vi=vcommon= 4.58m/s

At max height vf=0m/s

Use kinematic eqn in vertical direction

vf2= vi2 -2ghmax

Plugging values,

0^2=4.58^2-2*9.8*hmax

hmax=1.07m

4.58m/s

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