Im confused on this question, Please help. An aqueous solution is that 30.0 percent sulfuric acid...
Im confused on this question, Please help.
An aqueous solution is that 30.0 percent sulfuric acid (H2SO4) by mass has a density of 1.307g/mL. Determine the MOLALITY of the solution. Thank you in advance for your help. Very much appreciated!
Homework Answers
Molality is defined as the number of moles of solute per Kg of the solvent.
Suppose there is 100 g of the aqueous solution.
Mass of H2SO4 in the solution = 30 g
Moles of H2SO4 = 30 / 98 = 0.306 moles
Mass of Water (Solvent) = 70 g
Therefore there is 0.306 moles of solute in 70 g of solvent
Moles of solute in 1000 g (1 Kg) of solvent = 0.306 / 0.07 = 4.373 moles
Hence Molality = 4.373 m
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