Question

Calculate the determinant using cofactor expansion along any row or column. 1 0 3 1 1 1 -3 3 1 1 2 2 6 0 (a) 2 0 6 (b) -4 -2

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Answer #1

(a)llI A = 2 0 -3) 6 1 det (A) = ar cita 2 C12 ta 13 (13 . Ce & deffazz 023) 1 922 033) Gat det A2, A22 L Azi azal & det I A2Page No. Date del CA) - 110x5 - 6x01) - 1/2X5-6X1) + 13) ( 2XC-1) - 1x0) = 1 (0+6)-1(10-6) +3)(-2) 6- 4 + 6- (b) det (A)= -4 2 2 5 aet (A) = 31-285 - (5)x2 -1/-4x5 - (-5)*2) +1( (4) x2 - (-2)*2)) 3( -10 +10) - 11-20 +10) + (-8+4) 0+Page No 2 2 6 o 3 | 4 12 от было | Date du (A) е аtu Cu + 0 C + азизч+ 044 44 azy and any are zero, It is useless to find Czy

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