No. of moles= (given mass)/(molar mass)
Molar mass of HgO = 216.6 g/mol
So, 26.3 g HgO= (26.3/216.6) = 0.12 mol HgO
From the reaction stoichiometry we can say that,
2 mol HgO gives 1 mol O2 .
So, 0.12 mol HgO gives (1/2)×0.12 mol = 0.06 mol O2 .
Ideal gas equation: PV= nRT
Here, P= 0.941 atm, n= no. of moles= 0.06 mol,
T= 32°C = (273+32)K = 305 K, R= 0.082 L.atm/mol.K
0.941 atm× V= 0.06mole×0.082L.atm/mol.K × 305K
V= (0.06×0.082×305)/(0.941)
So, V= 1.6 L
Volume of O2 produced = 1.6 L
Oxygen can be produced by the thermal decomposition of mercuric oxide: heat 2 HgO(s) 2 Hg()...
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