A 20kg mass is moving with a speed of 25m/s. Calculate its kinetic energy A man...
2.A man pushes a lawn mower on a level lawn with a force of 250N. If 40% of the force is directed downward, how much work, in Joules, is done by the man in pushing the mower 6.Om? (10pts).
2 points) 7 A worker pushes done? horizcetally on a large crate with a force of 300 N, and the crate moved 5.0 m. How much work was LASO kg bag ofsugar is on a counter. How much work is done to put the bag on a shelfadístance of OAS m above the counter? 9.Aman pushes a lawn mower on a level lawn with a force 200 N. ir40% ofthe force is directed downward, how much work is done by...
A woman is pushing a lawn mower whose mass is 20kg across a horizontal yard. She pushes the mower with a force of 80 N that maintains a constant speed. What is the coefficient of friction? a.0.3 b.0.4 c.0.5 d.0.7 e.0.8
#1 a) Calculate the difference in kinetic energy when a 1300 kg car changes its speed from 90.0 m/s to 50.0 m/s. b) How much work is done on the car by friction force between the tires and road? Specify the sign of work. please answer both as they go together
A man pushing a crate of mass m = 92.0 kg at a speed of v = 0.845 m/s encounters a rough horizontal surface of length ℓ = 0.65 m as in the figure below. If the coefficient of kinetic friction between the crate and rough surface is 0.357 and he exerts a constant horizontal force of 292 N on the crate. A man pushes a crate labeled m, which moves with a velocity vector v to the right, on...
The energy of motion is called: Kinetic energy. potential energy, inertial energy. Power. In an inelastic collision: momentum is conserved. kinetic energy is conserved, both (a) and (b). If the velocity of a moving object is doubled and its mass is cut in half, the kinetic energy of the object is; remains the same, doubled quadrupled, cut in half. When the net work done on an object is speed of the object is me on an object is zero; the...
Hi, please help me check my answers for two physics problems. If they are wrong, please explain it so I could learn and correct the mistake. Thank you. [For the first problem, I got: push= 2598J, normal= 0, weight= 0, friction= -1920J. I calculated net work to be 678J ] [For the second problem, I got push=250J, normal and weight= 0, friction = -200J. I calculated net force to be 50J, which is positive] 3. A dockworker pushes a 50...
An electron with a kinetic energy equal to 40 J is moving in an electric field. The electric field produces a force the slow the electron to a stop. How much work in Joules is done on the electron? Enter only the numerical value. Submit response An electron with 50 J of energy enters a magnetic field. The magnetic field changes the direction of the electron to follow a helical path, but keeps a constant speed. How much work in...
A man pushing a crate of mass m= 920kg at a speed of V = 0.865 me encounters a rough horizontal surface of length 6–065m as in the figure below. If the coefficient of kinetic friction between the crate and rough surface is 0.353 and he exerts a constant horizontal force of 284 N on the crate. (a) Find the magnitude and direction of the net force on the crate while it is on the rough surface. magnitude direction --Select--...
An electron with a kinetic energy equal to 40 J is moving in an electric field. The electric field produces a force the slow the electron to a stop. How much work in Joules is done on the electron? Enter only the numerical value. Submit response An electron with 50 J of energy enters a magnetic field. The magnetic field changes the direction of the electron to follow a helical path, but keeps a constant speed. How much work in...