Question

^{What is the hydraulic cylinder retracted and extended length when theta' s maximum angle is 60 degrees and the minimum angle is 0 degrees.} At point D the platform weight is 650 lb acting downward. The dimensions are as follows: L = 20 ft. ABX = 1 (ft). ABY = 2 (ft). BC = 6 (ft).

L (feet) -BC (feet) → ABY (ft) 650 lb Centerline of rotation ABX (ft) 3 (ft) 8 (ft)

Answer 1

When theta = 0 degree therefore tan alpha = 2/5 longrightarrow alpha = tan^(-1)(2/5) = 21.8 degree therefore Min length of hydraulic cylinder sin alpha = (2/x_1) sin (21.8) 2/x_1 x_1 = 5.385 ft when theta = 60 degree cos 60 = x/() x = 3 ft sin 60 = y/6 y = 5.196 y approximate therefore tan beta = (7.2/2) beta = tan^(-1)(7.2/2) = 74.475 therefore Maximum length of hydraulic cylinder sin beta = 7.2/x_2 longrightarrow sin (74.475) = 7.2/x_2 x_2 = 7.473 ft