Question

3H2(g) + Ng Concept Check Question: NH HCO3 (MM = 79.07) is prepared by passing NHz with CO, into liquid H,O. Calculate the actual yield of NH HCO3 if the % yield is 74.7 % for the reaction of 14.8 g of NH3 (MM = 17.04) and 41.3 g of CO2 (MM = 44.01)? NH, + CO, + H20 NH HCO solve them for extra o A. 55.4 g B. 51.3 g C. 45.9 g D. 63.7 g E. 53.6 g 24

I have the answer but what's the correct formula

Answer 1

- NHy + log + Mgo y ah_Helly molar maut 17.04 44.01 79.07 mass 14.8. 46.03 taken No. of 0.87 0.93. moles. ed mole of NHg reacts with 1 mole of een produces 1 mold of NH. Heo - so here con is in excess & NHz is limiting reagent - 0.87 moles of cop reacts with 0,87 of NH, produces Jo 0.87 of N MyHcos We the beard yield z 0-87% 79.07 = 68.79 ~ 100%. - actual yield 3 68:79xx 74 7/100 = 54.389. Otac mail To enjoy life one should give up the lure of life