Homework Answers
Tukey Kramer test
| Level of significance | 0.05 |
| no. of treatments,k | 3 |
| DF error =N-k= | 153 |
| MSE | 1078.536 |
| q-statistic value(α,k,N-k) | 3.348 |
| fridays | satudays | sundays | |
| count, ni = | 52 | 52 | 52 |
| mean , x̅ i = | 396.769 | 441.712 | 390.135 |
critical value = q*√(MSE/2*(1/ni+1/nj)) = 15.2476
confidence interval = mean difference ± critical
value
if confidence interval contans zero, then means are not
different.
| confidence interval | |||||||
| population mean difference | critical value | lower limit | upper limit | result | |||
| µfridays-µsatudays | -44.942 | 15.2476 | -60.19 | -29.69 | yes,means are different | ||
| µfridays-µsundays | 6.635 | 15.2476 | -8.61 | 21.88 | no, means are not different | ||
| µsaturdays-µsundays | 51.577 | 15.2476 | 36.33 | 66.82 | yes, means are different | ||
Add Answer to:
Anova: Single Factor b. Use Tukey's HSD method at the 5% significance level to determine which...
A one-way analysis of varlance experlment produced the following ANOVA table. (You may find it us...
A one-way analysis of varlance experlment produced the following ANOVA table. (You may find it useful to reference the g table). SUMMARY Count Groups Column 1 Column 2 olumn 3 Source of Variation Between Groups Within Groups Total Average 8.89 1.31 2.35 SS 8.65 df 15 17 MS 4.33 0.26 16.65 8.6882 12.48 a. Conduct an ANOVA test at the 1% significance level to determine if some population means differ. o Reject Ho, we can conclude that some population means...
Chapter 13 Analysis of Variance Saved Help Save & Exl Chec 3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to...
Chapter 13 Analysis of Variance Saved Help Save & Exl Chec 3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the ttable and the gtable.) 10 points a. Calculate 99% confidence intervals for μ1-μ2, μ1 -μ3, and μ2-μ3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round...
CH13 Q3 The following statistics are computed by sampling from three normal populations whose variances are...
CH13 Q3
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) a. Calculate 99% confidence intervals for μ 1-2, μ1-#3, and μ2-#3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.) Population Mean Differences Can...
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You...
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the gtable.) X1 163, ni = 5; 2 = 171, n2 = 5; J3 = 166, n3 = 5; X4 = 158, n4 = 5; MSE = 41.2 a. Use Fisher's LSD method to determine which population means differ at a = 0.05. (Negative values should be indicated by a minus sign. Round intermediate...
Please help with b and c, thanks! A one-way analysis of variance experiment produced the following...
Please help with b and c, thanks! A one-way analysis of variance experiment produced the following ANOVA table. (You may find it useful to reference the q table). SUMMARY Groups Count Average Column 1 6 0.89 Column 2 6 1.31 Column 3 6 2.35 Source of Variation SS df MS F p-value Between Groups 8.65 2 4.33 16.65 0.0002 Within Groups 3.83 15 0.26 Total 12.48 17 b. Calculate 99% confidence interval estimates of μ1 − μ2,μ1 − μ3, and...
CH13 Q4 The following statistics are calculated by sampling from four normal populations whose variances are...
CH13 Q4
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) r1 = 137, n1 = 4; Tz = 144, n2 = 4; = 136, n3 = 4; T4 = 124, n4 = 4; MSE = 57.4 a. Use Fisher's LSD method to determine which population means differ at a- 0.01. (Negative values should be indicated by a minus sign....
Chapter 13 Analysis of Variance Saved Help Save & Exit Sub Check my work mode: This...
Chapter 13 Analysis of Variance Saved Help Save & Exit Sub Check my work mode: This shows what is correct or incorrect for the work you have completed so far. It does not indicate c Return to questio 4 The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) 10 points z = 153, n1 =6; 2 164, n2 =6; 23=...
CH13 Q7 Given a recent outbreak of illness caused by E. coli bacteria, the mayor in...
CH13 Q7
Given a recent outbreak of illness caused by E. coli bacteria, the mayor in a large city is concerned that some of his restaurant inspectors are not consistent with their evaluations of a restaurant's cleanliness In order to investigate this possibility, the mayor has five restaurant inspectors grade (scale of O to 100) the cleanliness of three restaurants. The results are shown in the accompanying table. (You may find it useful to reference the g table.) Restaurant Inspector...
The following output summarizes the results for a one-way analysis of variance experiment in which the...
The following output summarizes the results for a one-way analysis of variance experiment in which the treatments were three different hybrid cars and the variable measured was the miles per gallon (mpg) obtained while driving the same route. (You may find it useful to reference the g table.) Hybrid 1: ア1-33, n1-20 Hybrid 2:239, n2 - 15 Hybrid 3:29, n3 18 Source of Variation Between Groups Within Groups Total df 1,181.44 1,439.34 2,620.78 MS 590.72 28.79 p-value 0.0000 20.52 50...
CH13 Q7 Given a recent outbreak of illness caused by E. coli bacteria, the mayor in...
CH13 Q7
Given a recent outbreak of illness caused by E. coli bacteria, the mayor in a large city is concerned that some of his restaurant inspectors are not consistent with their evaluations of a restaurant's cleanliness. In order to investigate this possibility, the mayor has five restaurant inspectors grade (scale of O to 100) the cleanliness of three restaurants. The results are shown in the accompanying table. (You may find it useful to reference the g table.) 10 points...
A one-way analysis of varlance experlment produced the following ANOVA table. (You may find it useful to reference the g table). SUMMARY Count Groups Column 1 Column 2 olumn 3 Source of Variation Between Groups Within Groups Total Average 8.89 1.31 2.35 SS 8.65 df 15 17 MS 4.33 0.26 16.65 8.6882 12.48 a. Conduct an ANOVA test at the 1% significance level to determine if some population means differ. o Reject Ho, we can conclude that some population means...
Chapter 13 Analysis of Variance Saved Help Save & Exl Chec 3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the ttable and the gtable.) 10 points a. Calculate 99% confidence intervals for μ1-μ2, μ1 -μ3, and μ2-μ3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round...
CH13 Q3
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) a. Calculate 99% confidence intervals for μ 1-2, μ1-#3, and μ2-#3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.) Population Mean Differences Can...
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the gtable.) X1 163, ni = 5; 2 = 171, n2 = 5; J3 = 166, n3 = 5; X4 = 158, n4 = 5; MSE = 41.2 a. Use Fisher's LSD method to determine which population means differ at a = 0.05. (Negative values should be indicated by a minus sign. Round intermediate...
CH13 Q4
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) r1 = 137, n1 = 4; Tz = 144, n2 = 4; = 136, n3 = 4; T4 = 124, n4 = 4; MSE = 57.4 a. Use Fisher's LSD method to determine which population means differ at a- 0.01. (Negative values should be indicated by a minus sign....
Chapter 13 Analysis of Variance Saved Help Save & Exit Sub Check my work mode: This shows what is correct or incorrect for the work you have completed so far. It does not indicate c Return to questio 4 The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) 10 points z = 153, n1 =6; 2 164, n2 =6; 23=...
CH13 Q7
Given a recent outbreak of illness caused by E. coli bacteria, the mayor in a large city is concerned that some of his restaurant inspectors are not consistent with their evaluations of a restaurant's cleanliness In order to investigate this possibility, the mayor has five restaurant inspectors grade (scale of O to 100) the cleanliness of three restaurants. The results are shown in the accompanying table. (You may find it useful to reference the g table.) Restaurant Inspector...
The following output summarizes the results for a one-way analysis of variance experiment in which the treatments were three different hybrid cars and the variable measured was the miles per gallon (mpg) obtained while driving the same route. (You may find it useful to reference the g table.) Hybrid 1: ア1-33, n1-20 Hybrid 2:239, n2 - 15 Hybrid 3:29, n3 18 Source of Variation Between Groups Within Groups Total df 1,181.44 1,439.34 2,620.78 MS 590.72 28.79 p-value 0.0000 20.52 50...
CH13 Q7
Given a recent outbreak of illness caused by E. coli bacteria, the mayor in a large city is concerned that some of his restaurant inspectors are not consistent with their evaluations of a restaurant's cleanliness. In order to investigate this possibility, the mayor has five restaurant inspectors grade (scale of O to 100) the cleanliness of three restaurants. The results are shown in the accompanying table. (You may find it useful to reference the g table.) 10 points...
Most questions answered within 3 hours.
-
In response to high inflation in the United States, let us
assume that the Federal Reserve...
asked 27 minutes ago -
Which of the following is not an example of the public
health sector's responsibility?
a.immunization of...
asked 1 hour ago -
Search the Internet to find (at least 2 websites) related to the
general field of malware...
asked 2 hours ago -
A solution of methanoic acid, HCOOH (Ka = 1.8 ×
10-4) has pH 2.69. What amount...
asked 3 hours ago -
Nike Becomes a Global Citizen
Craig E. Johnson
In 1962, Stanford University student Phil Knight came...
asked 4 hours ago -
You have $35,000 to invest in a stock portfolio. Your choices
are Stock X with an...
asked 4 hours ago -
An ideal toroidal solenoid (Figure 1) has inner radius r1 = 15.5
cm and outer radius...
asked 7 hours ago -
A student sees her physical science professor approaching on the
sidewalk that runs by her dorm....
asked 8 hours ago -
I need to make up a critical incident report for client with
PTSD
asked 9 hours ago -
A champion athlete can produce one horsepower (746 W) for a
short period of time. If...
asked 10 hours ago -
Accidents_Daily_(X)
P(X)
0
0,26
1
0,29
2
0,17
3
0,11
4
0,08
5
0,06
6
0,03...
asked 10 hours ago -
1. Discuss how users can be authenticated by the operating
system to connect to the Oracle...
asked 10 hours ago