A certain rain cloud at an altitude of 2.07 km contains 3.20 ✕ 107 kg of water vapor. How long would it take for a 2.55-kW pump to raise the amount of water from Earth's surface to the cloud's position?
power = work/time
And,
work = force x distance = m g x h = 3.2x10^7kg x 9.8m/s/s x 2070 =
64915.2 * 10^7 J
Now,
2.55kW means 2550J/s are generated by this pump; therefore, it will
take a time of :
t = 64915.2x10^7J/2550J/s = 25.457 x 10^7 sec.
A certain rain cloud at an altitude of 2.07 km contains 3.20 ✕ 107 kg of...
A certain rain cloud at an altitude of 1.40 km contains 3.20 107 kg of water vapor. How long would it take for a 2.17-kW pump to raise the amount of water from Earth's surface to the cloud's position
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7. (Work and Energy) Atmospheric conditions near the Great Lakes are such that a cloud at an altitude of 1.50 km contains 3.20 ✕ 107 kg of water vapor. How long (in years) would it take for a 2.63 kW pump to raise this amount of water (at a constant speed) from Earth's surface to the altitude of the cloud?
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