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The mass m = 5.22 kg is sliding on the frictionless incline of angle 42.7 degrees...

The mass m = 5.22 kg is sliding on the frictionless incline of angle 42.7 degrees as shown. A force 3.6 N is applied horizontally as shown. Compute the normal force FN (in Newtons) that acts on the mass due to the incline. Use g = 9.8 m/s2 and express your result to three significant digits.

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Answer #1

Normal Force, FN= mgcostheta = 5.22*9.8 *cos42.7=37.595 N

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