Question

A mass of 65.7 kg is on a hill where the angle of the incline is...

A mass of 65.7 kg is on a hill where the angle of the incline is 23 degrees.

What is the component of the gravity force downhill? The unit is newtons. Just give me the magnitude to a reasonable number of significant figures.

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Answer #1

Given,

m = 65.7 kg ; theta = 23 deg

the component of force acting down the hill is:

Fy = mg sin(theta)

Fy = 65.7 x 9.8 x sin23 = 251.58 N

Hence, Fy = 251.58 N

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