ZuoTi.Pro
Question

A random sample of n = 500 observations from a binomial population produced x = 220...

A random sample of n = 500 observations from a binomial population produced x = 220 successes.

(a) Find a point estimate for p. Find the 95% margin of error for your estimator. (Round your answer to three decimal places.)

(b) Find a 90% confidence interval for p. (Round your answers to three decimal places.)

_____to_____

Interpret this interval.

a. In repeated sampling, 10% of all intervals constructed in this manner will enclose the population proportion.

b. In repeated sampling, 90% of all intervals constructed in this manner will enclose the population proportion.

c. There is a 10% chance that an individual sample proportion will fall within the interval.

d. 90% of all values will fall within the interval.

e. There is a 90% chance that an individual sample proportion will fall within the interval.

math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

500-and-X2 220 a> -A point est ima te for p is 220 p A 95 % comtidemle leve l level-of-significan le-o( =に0.95 cntical valut, o, os Zy2_ 1.96 using table (1.9640 44000.440 So o E 0.044

0 0
Add a comment
Know the answer?
Add Answer to:
A random sample of n = 500 observations from a binomial population produced x = 220...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • A random sample of n = 200 observations from a binomial population produced x = 190...

    A random sample of n = 200 observations from a binomial population produced x = 190 successes. Find a 90% confidence interval for p. (Round your answers to three decimal places.) _______ to _______ Interpret the interval. 90% of all values will fall within the interval. There is a 10% chance that an individual sample proportion will fall within the interval.     There is a 90% chance that an individual sample proportion will fall within the interval. In repeated sampling, 90%...

  • Find a 90% confidence interval for a population mean μ for these values. (Round your answers...

    Find a 90% confidence interval for a population mean μ for these values. (Round your answers to three decimal places.) (a) n = 105, x = 0.81, s2 = 0.089 (b) n = 90, x = 21.3, s2 = 3.53 (c) Interpret the intervals found in part (a) and part (b): A. There is a 10% chance that an individual sample proportion will fall within the interval. B. In repeated sampling, 90% of all intervals constructed in this manner will...

  • Find the necessary confidence interval for a population mean μ for the following values. (Round your...

    Find the necessary confidence interval for a population mean μ for the following values. (Round your answers to two decimal places.) α = 0.05, n = 83, x = 66.2, s2 = 2.38 to Interpret the interval that you have constructed. There is a 95% chance that an individual sample mean will fall within the interval.There is a 5% chance that an individual sample mean will fall within the interval.    In repeated sampling, 95% of all intervals constructed in this manner...

  • MY NOTES -/1 POINTS MENDSTAT15 7.5.012. Random samples of size n - were selected from a...

    MY NOTES -/1 POINTS MENDSTAT15 7.5.012. Random samples of size n - were selected from a binomial population with p -0.2. Use the normal distribution to approximate the following probability. (Round your answer to four de P(p < 0 10) = You may need to use the appropriate appendix table or technology to answer this question. MY NOTES 5. -13 POINTS MENDSTAT15 8.3.010. Find the necessary confidence interval for a population mean y for the following values. (Round your answers...

  • A random sample of n = 500 observations from a binomial population produced x = 169...

    A random sample of n = 500 observations from a binomial population produced x = 169 successes. Find a 90% confidence interval for p. (Round your answers to three decimal places

  • = 40 adults were selected from A small amount of the trace element selenium, 50-200 micrograms...

    = 40 adults were selected from A small amount of the trace element selenium, 50-200 micrograms (ug) per day, is considered essential to good health. Suppose that random samples of n, = n, two regions of the United States and that a day's intake of selenium was recorded for each person. The mean and standard deviation of the selenium daily intakes for the 40 adults from region 1 = 140.5 and s, = 17.1 µg. Find a 95% confidence interval...

  • A random sample of n = 400 observations from a binomial population produced x = 133...

    A random sample of n = 400 observations from a binomial population produced x = 133 successes. Give the best point estimate for the binomial proportion p. (Round your answer to three decimal places.) p̂ = Calculate the 95% margin of error. (Round your answer to three decimal places.) ______

  • -/1 POINTS MENDSTAT15 8.4.001. MY NOTES ASK YOUR TEACHER Independent random samples were selected from two...

    -/1 POINTS MENDSTAT15 8.4.001. MY NOTES ASK YOUR TEACHER Independent random samples were selected from two quantitative populations, with sample sizes, means, and variances given below. Sample Size Sample Mean Sample Variance Population 2 38 43 9.4 7.3 8.32 14.72 Construct a 90% confidence interval for the difference in the population means. (Use u, - \2. Round your answers to two decimal places.) to Construct a 99% confidence interval for the difference in the population means. (Round your answers to...

  • A random sample of n = 900 observations from a binomial population produced x = 655 successes

    A random sample of n = 900 observations from a binomial population produced x = 655 successes. Estimate the population proportion p and calculate the margin of error. (Please note, your estimate is a point estimate, and the margin of error is 1.96 x S.E.)

  • A random sample of size n = 40 is selected from a binomial distribution with population...

    A random sample of size n = 40 is selected from a binomial distribution with population proportion p = 0.25. Describe the approximate shape of the sampling distribution of p̂. approximately normalskewed left    uniformskewed right Calculate the mean and standard deviation (or standard error) of the sampling distribution of p̂. (Round your standard deviation to four decimal places.) mean standard deviation Find the probability that the sample proportion p̂ is between 0.15 and 0.41. (Round your answer to four decimal places.)

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT