Question

code needs to be written in c language.

Write a program that prints the type of the integer representation string provided by stdin. The possible types are "Decimal", "Octal", "Hexadecimal", or "Illegal". Example inputs: 118 rightarrow Decimal 074 rightarrow Octal 0xD5 rightarrow Hexadecimal cat rightarrow Illegal You can assume the input is between 1 and 9 characters (inclusive) long.

Answer 1

#include <stdio.h>
#include <string.h>
//Compiler version g++ 4.9

int main(void)
{
    char str[10];
    int octa=1,deci=1,hexa=1,i;
    printf("Enter the number : ");
    scanf("%s",str);
    printf("%s\n",str);
    for(i=0;i<strlen(str);i++)
    {
        if(i==0 && str[i]!=48)
        {
            octa=0;
        }
        else if(str[i]<48 || str[i]>55)
            octa=0;
           
        if(i==1)
        {
            if(!(str[i]==88 || str[i]==120))
                hexa=0;
        }
        else if(!isxdigit(str[i]))
            hexa=0;
        if(str[i]<48 || str[i]>57)
            deci=0;
       
    }
    printf("\n %s -> ",str);
    if(octa==1)
        printf("octal");
    else if(deci==1)
        printf("decimal");
    else if(hexa==1)
        printf("hexadecimal");
    else
        printf("illegal");
    return 0;
}