as both lens are of converging lens type,
if object is placed in between focus point and lens , the image formed is virtual
which is not desired in this scenario.
so the shorter focal length lens should be closer to the object
so that the you have more independence to move the object nearer to the lens without risking the image formed to be a virtual one.
Q2. total magnification=magnification of first lens*magnification of second lens
magnification of any lens=distance of image/distance of object
Q3. to be done in your lab.
Q4. calculate the object distance.
the focal length is known.
using thin lens equation, calculate the image distance.
place the screen at the distance calculated.
Q5. to be done by you in the lab.
Q6. use the thin lens equation and the object and image distance recorded by you
and then check that the thin lens equation is indeed obeyed
there might be a small variation owing to error in measurements but there should not be bigger variations
Don't quite get questions 1-6 For lenses in combination, the image for the first lens is...
Two converging lenses are separated by a distance of 20 cm. The first lens has a focal length of 5 cm and the second lens has an unknown focal length that you need to calculate. When an object is placed 8 cm in front of the first lens you measure a total magnification of M=-1.8 (That is, the magnification caused by the two lenses). Answer the following questions: 1. location of the image found by the first lens 2. magnification...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 2.00 cm -tall object is 57.0 cm to the left of a converging lens of focal length 40.0 cm . A second converging lens, this one having a focal length of 60.0 cm , is...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.70-cm-tall object is 55.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 2.00 cm -tall object is 57.0 cm to the left of a converging lens of focal length 40.0 cm . A second converging lens, this one having a focal length of 60.0 cm , is...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 2.00 cm-tall object is 50.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.90cm -tall object is 51.0cm to the left of a converging lens of focal length 40.0cm . A second converging lens, this one having a focal length of 60.0cm , is located 300cm to the...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20-cm-tall object is 50.0 cm to the left of a lens of focal length of magnitude 40.0 cm. A second lens, this one having a focal length of magnitude 60.0 cm, is located 300.0 cm...
When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.80 cm -tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm . A second converging lens, this one having a focal length of 60.0 cm , is...
Two positive thin lenses are separated by a distance of d. The focal lengths of the lenses are f_1 = 10 cm and f_2 = 20 cm. The desired throw of the system, the object to image distance, is T = 80 cm and the desired magnification is M = -1.1. a) Use what you know about the conjugate matrix for a two lens system to solve to the distance between the lenses. Express your answer in cm. b) Where...
webassign.net Active Figure 26.25 Thin Lenses The animation below shows a thin lens, an object (blue arrow) and an image (tan arrow). Three rays are shown that locate the positic orientation, and size of the image. Readouts are provided for object distance, object height, image distance and image height. Instructions: Click and drag the blue object. Click the button in the lower left of the applet window to toggle between a conc convex lens. Explore Images formed by thin lenses...