A girl jogs around a horizontally circle with a constant speed. She travels one fourth of...
A girl jogs around a horizontally circle with a constant speed. She travels one fourth of a revolution, a distance of 20.1 m along the circumference of the circle, in 4.7 s. The magnitude of her acceleration is ____ m/s2. Round your answer to the nearest tenth. Do not use scientific notation.
Homework Answers
formula for centripetal accleration is
a= v^2/r
since v= 2pi r/T
= 2pi ( C/ 2pi)/T
= C/T
a= ( C/T)^2/r
--------------------------------------------------------------------------------------------------
( 2pi r/4) = 20.1 m
r= 12.8 m
a= ( 20.1/4.7)^2/12.8 m
=1.42 m/s^2
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