Homework Answers
a] Let the angle be theta
tan theta = (133/2)/50.5e3 = 0.001317
theta = arctan 0.001317 = 0.07546 degree
b] New angle theta = 0.07546 + 0.005 degree = 0.08046 degree
tan theta = tan 0.08046 degree = 0.001404
New separation between source and sensor = 2*50.5e3 tan theta = 2*50.5e3*0.001404 = 141.8 m
So he needs to move 141.8-133 = 8.8 m south answer
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