Question

< HWK #18 Fundamental Problem 5.1 1 of7 Part A Determine the horizontal and vertical components of reaction at the supports. Neglect the thickness of the beam. (Figure 1) Draw the free-body diagram of the beam. Draw the vectors starting at the black dots. The location and orientation of the vectors will be graded. Label vectors A Reaction at point A, horizontal ▲ Length: -Angle: 0 Start point x:-y-End Point x-y- 500 lb Figure 1 of 1 600 lb f 5 ft 500 lb 600 lb ft 5 ft 5 ft Press ENTER r SPACE to see the list of the elements that can be added to the canvas. Press TAB to move to the next menu option. Press | CTRL-Y | to get to the elements on the canvas. Press | CTRL+ to quit the application.

determine the direction for Ax, Ay,Bx,By

STATICS

Answer 1

The free body diagram of the system is neglecting the thickness of beam In Roll on support, there will be no horizontal reaction By equilibrium of Horizontal forces E_Ax + 500 times 3/5 = 0 implies R_Ax = -300 lb Acting in the direction of - x axis (leftward) By equilibrium of vertical forces R_Ay + R_By = 500 times 4/5 = 400 lb - (i) Taking moments about �A�, i.e. sigma M_A = 0 implies 500 times 4/5 times 5 + 600 = R_By times 100 implies R_By = 260 lb Taking moments about �B�, i.e. sigma M_B = 0 implies R_Ay times 10 + 600 = 500 times 4/5 times 5 implies R_Ay = 140 lb so equation (i) also satisfies