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A 2.80 kg rock has a horizontal velocity of magnitude 12.0 m/s when it is at point P in the figure (Figure 1). 1 of 1 Figure
Part A At this instant, what is the magnitude of its angular momentum relative to point O? VO AD ? L= m2/s Submit Request Ans
Part C If the only force acting on the rock is its weight, what is the magnitude of the rate of change of its angular momentu
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Rate of change of angular momentum is equal to torque. We use this fact to find the required magnitude and direction as shown belowA) 2------ r= (8m) sino), 0 = 36.90 = 4.8m → perpendicular distance - of line of velocity from pt. o. So, L=mur (22m/s) = 161

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